In a race, the odd favour of cars P,Q,R,S are 1:3, 1:4, 1:5 and 1:6 respectively. Find the probability that one of them wins the race.
P(P)=14,P(Q)=15,P(R)=16,P(S)=17All the events are mutually exclusive hence,
Required probability = P(P)+P(Q)+P(R)+P(S)
14+15+16+17=319420
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