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Q:

A sequence a, ax, ax2, ......, axn, has odd number of terms. Then the median is

 

A) axn2+1 B) axn2-1
C) axn-1 D) axn2

Answer:   D) axn2



Explanation:
Subject: Probability
Exam Prep: Bank Exams
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Q:

The probability that a card drawn at random from the pack of playing cards may be either a queen or an ace is:

A) 9/13 B) 11/13
C) 2/13 D) None of these
 
Answer & Explanation Answer: C) 2/13

Explanation:

Number of queen cards = 4

Number of ace cards = 4

 P(either a queen or ace) = 4/52 + 4/52= 8/52 = 2/13

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3 7836
Q:

If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?

A) 1/6 B) 1/2
C) 1/3 D) 1/4
 
Answer & Explanation Answer: A) 1/6

Explanation:

P(first letter is not vowel) = 24

 

P(second letter is not vowel) = 13

 

So, probability that none of letters would be vowels is = 24×13=16

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67 22783
Q:

If an unbiased dice is rolled once, the odds in favour of getting a point which is multiple of 3 is:

A) 1/2 B) 2/1
C) 1/3 D) 3/1
 
Answer & Explanation Answer: C) 1/3

Explanation:

Total number =6

Getting a 'multiple of 3' = 2 . So, probability = 2/6 =1/3

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15 10845
Q:

If a card is drawn at random from a pack of 52 cards,what is the chance of getting a spade or ace?

A) 0.25 B) 5/13
C) 0.20 D) 4/13
 
Answer & Explanation Answer: D) 4/13

Explanation:

Number of spades in a standard deck of cards=13
Number of aces in a standard deck of cards=4
And,one of the aces is a spade.
So, 13 + 4 - 1 = 16 spades or aces to choose from.
Therfore,probabiltiy of getting a spade or an ace=16/52=4/13

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18 17197
Q:

A number is selected from the numbers 1,2,3,4.......25.The probability for it to be divisible by 4 or 7 is:

A) 3/25 B) 9/25
C) 1/25 D) None of these
 
Answer & Explanation Answer: B) 9/25

Explanation:

Total numbers = 25

 Numbers divisible by 4 or 7 are 4, 7, 8, 12, 14, 16, 20, 21, 24 = 9

 

 The probability (divisible by 4 or 7) = 9/25

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3 7435
Q:

If P(A)=4/9;then the odd against the event A is:

A) 4:9 B) 4:5
C) 5:4 D) 4:14
 
Answer & Explanation Answer: C) 5:4

Explanation:

Here,P(A)=4/9=p/(p+q)

P(odd against event A)=q/p=5/4

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11 10138
Q:

If p:q are the odds in favour of an event,then the probability of that event is:

A) p/q B) p/(p+q)
C) q/(p+q) D) none
 
Answer & Explanation Answer: B) p/(p+q)

Explanation:

Total number of cases=p+q

Favourable cases=p

Probability of that event is=p/(p+q)

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7 10466
Q:

The probabiltiy that throw of two dice yields a total of 5 or 6 is:

A) 2/14 B) 5/18
C) 3/4 D) 1/4
 
Answer & Explanation Answer: B) 5/18

Explanation:

Total number of cases=36

Number of favourable cases(sum 5 or 6)=10

P(getting total of 5 or 6)=10/36=5/18

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5 5766