Sawaal
12
Q:

Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K? 

A) K1k2/k1+k2 B) 2k1k2/k1+k2
C) K1+k2/k1k2 D) None

Answer:   B) 2k1k2/k1+k2



Explanation:

We know that,

 

The equivalent K =  L1 + L2L1K1+L2K2

 

where L1 & L2 are plate1 & Plate2 thicknesses, K1 & K2 are coefficient thermal conductivity of plate1 & Plate2 respectively.

 

But here L1 = L2 = L (say)

 

Then K = L+L/(L/K1 + L/K2)  =  2K1K2K1+K2

Subject: Physics
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