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Q:

For a certain reaction,DGq = -45 kJ/mol and DHq= -90 kJ/mol at 0°C. What is the minimum temperature at which the reaction will become spontaneous, ifDHq and DSq are independent of temperature?

A) 273 K B) 298 K
C) 546 K D) 596 K

Answer:   C) 546 K



Explanation:

T = 273 °K

Using the formula,

DGq = DHq –TDS

-45 = -90 –273 DS

DS = 0.164

Now since DHq and DSq are independent,T2= DH/DS = 45/0.164 = 273°K

Required Temp = 273 + 273 = 546°K

Subject: Physics
Exam Prep: Bank Exams
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