Sawaal
8
Q:

A ball is thrown vertically upward from the ground. It crosses a point at the height of 25 m twice at an interval of 4 seconds. The ball was thrown with the velocity of

A) 18 m/s B) 25 m/s
C) 30 m/s D) 36 m/s

Answer:   C) 30 m/s



Explanation:

The interval between object pass the same point is 4 sec.

That means in 2 sec, object reaches the top and in next 2 sec, it again reaches the same point.

By the info given, we can find the velocity of that point by using : v=u+(-gt)

0= u - 10×2

u = 20

Then the velocity at 25m is 20m/sec.

so the initial velocity is


-v2 = u2 + (-2gh)400 = u2 - 2x 10 x 25u2 = 900 => u = 30 m/s

Subject: Physics
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