If one needs to score 34% to pass a test, the pass | Percentage Questions & Answers

Q:

What will come in place of the question mark(?) in the following question ?

56% of 870 + 82% of 180 = 32% of 90 + ?

A) 777	B) 666
C) 606	D) 789

Answer & Explanation Answer: C) 606

Explanation:

56% of 870 = 56x870/100 = 487.20

82% of 180 = 82x180/100 = 147.60

32% of 90 = 32x90/100

487.20 + 147.6 - 28.8 = ?

? = 634.8 - 28.8

? = 606.

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Q:

The price of a car is increased by 25%, by how much percent, must the new price of this car be decreased to restore its original price ?

A) 20%	B) 24%
C) 21%	D) 25%

Answer & Explanation Answer: A) 20%

Explanation:

Suppose that the original price of the car = Rs. x

Then new price of the car

$= x + x \times \frac{25}{100} = \frac{5}{4} x R s$

To restore the original price, the new price must be decreased by

$\frac{5}{4} x - x = \frac{x}{4} R s$

So required percentage $= \frac{\frac{x}{4}}{\frac{5}{4} x} \times 100 %$

= 20%

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Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000	B) Rs.4500
C) Rs.7500	D) Rs.5000

Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Q:

A man reduces his travelling time by a fraction of 2/5, as a result the distance covered by the man is increased by 20%, find the percentage increase in the speed of the man ?

A) 77%	B) 88%
C) 100%	D) 99%

Answer & Explanation Answer: C) 100%

Explanation:

IBPS RRB Clerk Level Quiz : Quantitative Aptitude | 15 -09 - 17

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Q:

60 percent of 2/7 of three-fourth of a number is 2664. What is the number ?

A) 20720	B) 21352
C) 25421	D) 24150

Answer & Explanation Answer: A) 20720

Explanation:

Let N be the required number.

=> $\frac{60}{100} x \frac{2}{7} x \frac{3}{4} x N = 2664$

=> N = 2664x2x7x5/9

=> N = 20720.

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Q:

At an examination in which maximum marks are 500. K got 10% less than L, L got 25% more than M and M got 20% less than N. If K got 360 marks what percentage of marks was obtained by N ?

A) 80	B) 87
C) 78	D) 76

Answer & Explanation Answer: A) 80

Explanation:

Let marks obtained by N = x

M's marks = 0.80x

L's marks = 1.25 (0.80x)

K's marks = (0.90) (1.25) (0.80x)

= 0.9x

But 0.9x = 360 ⇒ x = 400

Percentage of Marks obtained by N

= 400 x 100/500 = 80%

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Q:

A girl want to read a complete book. She read 2/5 part of a book on 1st day, 34% on second day and remaining pages in next two days. On those two days she read equal number of pages. If she read 52 pages on last day, then find out total number of pages that the book contain ?

A) 400	B) 525
C) 325	D) 475

Answer & Explanation Answer: A) 400

Explanation:

Let the total number of pages in the book be 'x'.

From given data,

2x/5 + 34x/100 + 52 + 52 = x

=> 40x + 34x + 10400 = 100x

=> 26x = 10400

=> x = 400.

Hence, total pages in the book are 400.

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Q:

In a school of 1500 boys, 35% are Hindu, 30% are Sikh,15% are Muslims and remainning are Christians. Find number of christian boys in the school ?

Answer

Given total number of boys in the school = 1500

In that 35% are Hindu, 30% are Sikh, 15% are Muslims

=> 35 + 30 + 15 = 80%

Remaining Boys = 100% - 80% = 20% of 1500

=> 20 x 1500/100 = 300 boys are Christians.

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A) 13.2	B) 14.2
C) 13.6	D) 14.6

If one needs to score 34% to pass a test, the pass marks out of 40 would be:

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