If one needs to score 34% to pass a test, the pass marks out of 40 would be:

 

Quantity of pure acid = 20% of 8 litres = ((20/100)*8) litres = 1.6 litres.

The fruit content in both the fresh fruit and dry fruit is the same.

Given, fresh fruit has 68% water.so remaining 32% is fruit content. weight of fresh fruits is 100kg

Dry fruit has 20% water.so remaining 80% is fruit content.let weight if dry fruit be y kg.

Fruit % in freshfruit = Fruit% in dryfruit 

Therefore, (32/100) x 100 = (80/100 ) x y 

we get, y = 40 kg.

Present population =  160000 *  (1 + 3/100)(1 + 5/200)(1 + 5/100)= 177366.

Given that the student got 125 marks and still he failed by 40 marks

=> The minimum pass mark = 125 + 40 = 165

Given that minimum pass mark = 33% of the total mark

=> total mark =33/100 =165

=> total mark = 16500/33 = 500

Saving  = 50% of (100 - 40)% of (100 - 30)% of Rs. 18,400 = Rs. (50/100 * 60/100 * 70/100 * 18400) = Rs. 3864.

n (A) = 34, n (B) = 42, n (A  ∩ B) = 20.

So, n (A  U B) = n (A) + n(B) - n(A ∩B) = 34 + 42 - 20 = 56.

Percentage failed in either or both the subjects = 56.

Hence, percentage passed = (100 - 66)% = 44%.

Actual price = Rs. (25 + 2.50) = Rs. 27.50. 

Saving = 2.50

Percentage Saving = [(2.50/27.50)*100]

= 2500/275

= 9111%

≈9%

Pass percentage  =[(252/270)*100] % =280/3 % =9313 9 %