(3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ?
(3x + 2) (2x - 5) = ax2+kx+n ...............(1)
But (3x + 2)(2x - 5) = 6x2-11x-10........(2)
so by comparing (1) & (2),
we get a= 6, k= -11 , n= -10
(a - n + k) = 6 + 10 - 11 = 5.
Which number will fit in '?' place in the following series?
12, 23, 45, 89, ?
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