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23
Q:

The last two digits of 2151415?

A) 81 B) 61
C) 91 D) 51

Answer:   D) 51



Explanation:

Unit digit of this expression is always 1 as the base ends with 1. 

For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.

i.e, tenth place digit in 2151 is 5 and

tenth place digit in power 415 is 1

And the units digit in the product of 5 x 1 = 5

 

Therefore, last two digits of 2151415 is 51.

Subject: Mathematical Operations
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