Sawaal
38
Q:

The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is

A) 1677 B) 1683
C) 2523 D) 3363

Answer:   B) 1683



Explanation:

 L.C.M of 5, 6, 7, 8 = 840

 

Therefore, Required Number is of the form 840k+3.

 

Least value of k for which (840k+3) is divisible by 9 is k = 2 

 

Therefore, Required  Number = (840 x 2+3)=1683

Subject: HCF and LCM
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