CAT Questions

Q:

Solve the math puzzle given below?

math_puzzle1541075516.jpg image

A) 14 B) 10
C) 9 D) 8
 
Answer & Explanation Answer: B) 10

Explanation:
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77 8846
Q:

If 12 men can reap 120 acres of land in 36 days, how many acres of land can 54 men reap in 54 days?

A) 710 acres B) 760 acres
C) 810 acres D) 860 acres
 
Answer & Explanation Answer: C) 810 acres

Explanation:

12 men120 acres36 days54 men?54 days

 As 12 men can reap 120 acres, 54 men will be able to reap more acres in 36 days, 120 acres of land was reaped, so in 54 days, more land will be reaped.

 

Thus, the numbers of acres that can be reaped by 54 men in 54 days = 5412x120x5436 = 810 acres

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Filed Under: Ratios and Proportions
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19 8842
Q:

Alexander, the Great invaded India during the rule of ?

A) Mahapadma Nanda B) Dhana Nanda
C) Ajatshatru D) Bimbisara
 
Answer & Explanation Answer: B) Dhana Nanda

Explanation:
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21 8842
Q:

Select the related word/letters/numbers from the given alternatives:

Words : Sentence :: Paragraph: ?

A) TYPING B) Essay
C) Letters D) Phrase
 
Answer & Explanation Answer: B) Essay

Explanation:
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Q:

Deccan Education Society was founded by

deccan_education_society_was_founded_by1553511683.jpg image

A) Bal Gangadhar Tilak B) Jyotiba Phule
C) Firoz Shah Mehta D) Gopal Ganesh Agarkar
 
Answer & Explanation Answer: A) Bal Gangadhar Tilak

Explanation:

Deccan education society is an organization which runs 43 education establishments in Maharastra, Pune founded by Bal Gangadhar Tilak.

Deccan_Education_Society_was_founded_by11553511766.jpg image

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Filed Under: Indian History
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8 8823
Q:

From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is 

A) 81.92L B) 96L
C) 118.08L D) None of these
 
Answer & Explanation Answer: C) 118.08L

Explanation:

The amount of petrol left after 4 operations  

200 × 1-402004  

200 × 454  

200 × 256625  

= 81.92 litres

 

Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres

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Filed Under: Alligation or Mixture
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9 8820
Q:

Anu's present age is 9 years more than that of what Raj's age will be after five years. Raj's present age is seven years more than that of what Renu's age was 4 years ago. Renu's present age is 19 years. What will be Anu's age after 5 years ?

A) 39 yrs B) 36 yrs
C) 46 yrs D) 41 yrs
 
Answer & Explanation Answer: D) 41 yrs

Explanation:

Anu = (Raj + 5) + 9

= Raj + 14 -------- (I)

Raj = (Renu - 4) + 7

= Renu + 3 ------- (II)

Raj's age = 19 + 3 = 22 years

After 5 years Anu's age = 22 + 14 + 5 = 41 years

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Filed Under: Problems on Ages
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9 8819
Q:

A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ?

A) 24 - 1  

B) 2425-1   

C) (24-1)(23-1)25   

D) None 

A) A B) B
C) C D) D
 
Answer & Explanation Answer: C) C

Explanation:

It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects.

 

Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection.

 

Hence, we can select 1 black ball from 4 black balls
or 2 black balls from 4 black balls.
or 3 black balls from 4 black balls.
or 4 black balls from 4 black balls.

 

Hence, number of ways in which we can select the black balls

 

= 4C1 + 4C2 + 4C3 + 4C4
= 24-1 ........(A)

 

Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection.

 

Hence, we can select 1 red ball from 3 red balls
or 2 red balls from 3 red balls
or 3 red balls from 3 red balls

 

Hence, number of ways in which we can select the red balls
= 3C1 + 3C2 + 3C3
=23-1........(B)

 

Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)
or 1 blue ball from 5 blue balls
or 2 blue balls from 5 blue balls
or 3 blue balls from 5 blue balls
or 4 blue balls from 5 blue balls
or 5 blue balls from 5 blue balls.

 

Hence, number of ways in which we can select the blue balls
= 5C0 + 5C1 + 5C2 + … + 5C5
= 25..............(C)

 

From (A), (B) and (C), required number of ways
=  2524-123-1

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