Three taps I, J and K can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 70 minutes. What is the total time taken for the completely full ?
Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120
For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120
So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120 So remaining tank = 13/120
Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280. So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes
Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.
Tally is one of the best business accounting software for accounting, inventory, payroll. It is economical and one of the most popular ERP software solutions available in the industry.
Tally, an accounting software was developed by the multinational company TCS - Tata Consultancy Services.
Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time
so 1/3rd of the usual time = 15min or usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.
A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current?