Running at the same constant rate, 6 identical mac | Chain Rule Questions & Answers

Q:

If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ?

A) 78 paise	B) 48 paise
C) 54 paise	D) 62 paise

Answer & Explanation Answer: B) 48 paise

Explanation:

Quarter of Kg means 250 gm

Less weight, less price (Direct Proportion)

So,

250 : 200 :: 60 : x => x = 48

So 200 gm will cost 48 paise.

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Q:

The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?

A) 14th element	B) 9th element
C) 12th element	D) 7th element

Answer & Explanation Answer: C) 12th element

Explanation:

If we consider the third term to be ‘x”
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.

Thus, 12th term of the A.P will be zero.

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35 12562

Q:

In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ?

A) 18	B) 14
C) 22	D) 24

Answer & Explanation Answer: B) 14

Explanation:

1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14
Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between them
So minimum no. of boys standing in the queue = 14

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28 4967

Q:

If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?

A) Rs. 175	B) Rs. 325
C) Rs. 340	D) Rs. 260

Answer & Explanation Answer: C) Rs. 340

Explanation:

Assume first child (the youngest) get = Rs. x

According to the question ;
each son having Rs. 30 more than the younger one

Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120

Total amount they got = Rs. 2000

x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.

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22 5309

Q:

An industrial loom weaves 1.14 meters of cloth every second. Approximately, how much time will it take to weave 52 meters of cloth ?

A) 29.32 sec	B) 42.51 sec
C) 39.25 sec	D) 45.61 sec

Answer & Explanation Answer: D) 45.61 sec

Explanation:

Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in,

1.14 ----- 1

52.0 ------?

$\Rightarrow \frac{52}{1.14}$ = 45.61 sec

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Q:

If 36 men can do a piece of work in 25 hours, in how mwny hours will15 men do it?

A) 40	B) 50
C) 60	D) 70

Answer & Explanation Answer: C) 60

Explanation:

Let the required no of hours be x. Then

Less men , More hours (Indirct Proportion)

Therefore, 15:36 ::25:x

=> (15 x X)=(36 x 25) => x = 60

Hence, 15 men can do it in 60 hours.

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Q:

If 20 men can build a wall 56 meters long in 6 days , what length of a similar wall can be built by 35 men in 3 days?

A) 46	B) 47
C) 48	D) 49

Answer & Explanation Answer: D) 49

Explanation:

Let the required length be x meters

More men, More length built (Direct proportion)

Less days, Less length built (Direct Proportion)

$\begin{array}{r} \begin{matrix} M e n & 20 : 35 \end{matrix} \\ \begin{matrix} D a y s & 6 : 3 \end{matrix} \end{array}\} ⋮ ⋮ 56 : x$

=> (20 x 6 x X)=(35 x 3 x 56)

=> x = 49

Hence, the required length is 49 m.

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Q:

2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in

A) 18 days	B) 21 days
C) 24 days	D) 30 days

Answer & Explanation Answer: B) 21 days

Explanation:

(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys

=>5 men= 10 boys => 1man= 2 boys

Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys

( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.

Let the required number of days be x.

More boys , Less days (Indirect proportion)

More work , More days (Direct proportion)

$\begin{array}{r} \begin{matrix} B o y s & 22 : 11 \end{matrix} \\ \begin{matrix} W o r k & 1 : 3 \end{matrix} \end{array}\} ⋮ ⋮ 14 : x$

A) 648	B) 1800
C) 2700	D) 10800

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

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