1
Q:
A) /24 | B) /25 |
C) /26 | D) /27 |
Answer: C) /26
Explanation:
Explanation:
Explanation: 50 hosts require 6 bits of the last octet giving us 64 -2 = 62 possible hosts this satisfies our requirement and leaves us 2 bits over for the subnets. The default mask is /24 or 255.255.255.0 adding the 2 bits for the subnets it becomes 255.255.255.192 or /26