6
Q:
A) A | B) B |
C) C | D) D |
Answer: B) B
Explanation:
Explanation:
D _ C _ A --------(1)
D > B > C --------(2)
from (1) and (2)
D > B > C > A ---------(3)
Again E _ B _ A
But B > A, from (3)
So E > D > B > C > A [ Since B is the average of E and A so it is eqidistant from both E and A]