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13
Q:

Of the following, which is greater than ½ ?

Indicate ALL such fractions.

A) 2/5 B) 4/7
C) 4/9 D) 5/11

Answer:   B) 4/7



Explanation:

One way to deal with fractions is to convert them all to decimals. 

In this case all you would need to do is to see which is greater than 0.5.

Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7. 

Subject: Average
Exam Prep: GRE
Related Questions
Q:

8 years ago there were 5 members in the Arthur's family and then the average age of the family  was 36 years. Mean while Arthur got married and gave birth to a child. Still the average age of his family is same now. What is the age of his wife at the time of his child's birth was.If the difference between the age of her  child and herself was 26 years.

A) 25 years B) 26 years
C) 20 years D) can't be determined
 
Answer & Explanation Answer: B) 26 years

Explanation:

Since we know that the difference b/w the age of any two persons remains always constant, while the ratio of their ages gets changed as the time changes.

 

so, if the age of his child be x (presently)

 

Then the age of  wife be x + 26 (presently)

 

Thus the total age = x + ( x + 26) = 32  [∵252-220 =32]

=> x = 3

Therefore, The age of her child is 3 years and her self  is 29 years. Hence her age at the time of the birth of her child was 26 years.

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12 11490
Q:

The average of any 5 consecutive odd natural numbers is k . If two more such numbers , just next to the previous 5 numbers are added , the new average becomes

A) 2(k+1) B) 2k-3
C) 2k+1 D) k+2
 
Answer & Explanation Answer: D) k+2

Explanation:

The 5 consecutive odd numbers whose average is k are  (k-4), (k-2), k, (k+2), (k+4)

Again the average of (k-4), (k-2), k, (k+2), (k+4), (k+6), (k+8) is (k+2)

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14 15803
Q:

The average value of property of Mittal, Ambani and Singhania is Rs.11111 crore. The property of Singhania is as less than the property of Mittal is greater than the average property of both the Singhania and Mittal. The value of property of Ambani is :

A) Rs.111 crore B) Rs. 1111 crore
C) Rs. 11111 crore D) can't be determined
 
Answer & Explanation Answer: C) Rs. 11111 crore

Explanation:

M+A+S3=11111 

 

also S+M2=11111   (∵ M - 11111 = 11111 - S) 

 

=>A = 11111

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13 19634
Q:

Amithab's average expenditure for the January to June is Rs. 4200 and he spends Rs.1200 in January and Rs.1500 in july.The average expenditure for the months of febraury to July is:

A) Rs. 4250 B) Rs. 4520
C) Rs. 4060 D) None of these
 
Answer & Explanation Answer: A) Rs. 4250

Explanation:

Amithab's total expenditure for Jan - June  = 4200 x 6 = 25200

 

Expenditure for Feb - June = 25200-1200 = 24000

 

Expenditure for the months of Feb - July = 24000 + 1500 =25500

 

The average expenditure = 25500/6 = 4250

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9 10999
Q:

In a village the average age of n people is 42 years. But after the verification it was found that the age of a person had been  considered 20 years less than the actual age, so the new average, after the correction,increased by 1. The value of n is :

A) 21 B) 20
C) 22 D) None of these
 
Answer & Explanation Answer: B) 20

Explanation:

It is the same as a person with 20 years more age  replaces an existing person of the group ( or village)

Since the total age of the village having n persons, is being increased by 20 years and the average age of village is being increased by 1 year, hence there are total 20 people in the village.

 

Alternatively :  ( n x 42 ) + 20 = ( n x 43 )

                          => n=20

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14 16675
Q:

123 typists typeed 984 papers in 1/15 hour. The number of papers typed for  minute by a average typist is:

A) 1 B) 2
C) 3 D) 5
 
Answer & Explanation Answer: B) 2

Explanation:

Use unitary method:

In \inline \frac{1}{15} hours, 123 typists can type 984 paper

In 1 minute, 123 typists can type  \inline \frac{984}{4} = 246 papers

In 1 minute, 1 typist can type \inline \frac{246}{123} =2 papers      [ Hint \inline \frac{1}{15} hours = 4 minutes]

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20 13482
Q:

What is the average of four tenths and five thousandths

A) 25002 B) 2502
C) 0.2025 D) none
 
Answer & Explanation Answer: C) 0.2025

Explanation:

Four tenths = 0.4

Five thousandths = 0.005

The average is (0.4 + 0.005)/2 = 0.2025

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Exam Prep: GRE

12 13812
Q:

In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

A) 6 B) 12
C) 24 D) 18
 
Answer & Explanation Answer: C) 24

Explanation:

You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither

78 = (41-9) + (22-9) + 9 + neither.

Not enrolled students = 24

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20 21612