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13
Q:

Of the following, which is greater than ½ ?

Indicate ALL such fractions.

A) 2/5 B) 4/7
C) 4/9 D) 5/11

Answer:   B) 4/7



Explanation:

One way to deal with fractions is to convert them all to decimals. 

In this case all you would need to do is to see which is greater than 0.5.

Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7. 

Subject: Average
Exam Prep: GRE
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Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was 79 and the average marks in the last 3 subjects was 86. If his marks in the third subject was 80, then what was his average marks in all the 5 subjects?

A) 81 B) 82
C) 83 D) 85
 
Answer & Explanation Answer: C) 83

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For the data given below. find the sum of mode. median and mean.6, 3, 8, 4, 3, 11, 7, 4, 5, 4.

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Answer & Explanation Answer: C) 14

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The median of the numbers 14, 12, 12, 16, 13 and 18 is

A) 13 B) 14
C) 14.5 D) 13.5
 
Answer & Explanation Answer: D) 13.5

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The mean height of 25 boys in a class is 150 cm, and the mean height of 35 girls in the same class is 145 cm. The combined mean height of 60 students in the class is ___ (app)

A) 146 B) 143
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Answer & Explanation Answer: C) 147

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Q:

The average weight of two players P and Q of a football team is 38 kg. The average weight of P, Q and their coach T is 49 kg. What is the weight (in kg) of coach?

A) 71 B) 46
C) 76 D) 91
 
Answer & Explanation Answer: A) 71

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Q:

After replacing an old member by a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. The difference between the ages of the replaced and the new members?

A) 16 years B) 15 years
C) 14 years D) 13 years
 
Answer & Explanation Answer: B) 15 years

Explanation:

Let avg ages of 5 members at present is G

And age of new member is m and an older is n

Required = (5G + m - n)/5 = G - 3

m - n = 15 years

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Q:

A student's average marks in five subjects is 82. If the average marks of first two subject is 86.5 and the average marks of last two subjects is 84. Find the marks of third subject?

A) 69 B) 67
C) 71 D) 73
 
Answer & Explanation Answer: A) 69

Explanation:

The total marks of all 5 subjects = 82 x 5 = 410

Total marks of 1st two subjects = 86.5 x 2 = 173

Total marks of last two subjects = 84 x 2 = 168

Now, marks in 3rd subject = 410 - (173 + 168) = 410 - 341 = 69.

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Q:

Find the average of first 50 natural numbers?

A) 25 B) 25.5
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Answer & Explanation Answer: B) 25.5

Explanation:

We Know that sum of the n natural numbers =n(n+1)2

  

Then sum of 50 natural numbers= 50(51)2= 1250

  

Average of the 50 natural numbers = 125050 = 25.5

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