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Q:

Consider the following frequency distribution:

x     f

8     6

5     4

6     5

10    8

9     9

4     6

7     4

What is the median for the distribution?

A) 6 B) 7
C) 8 D) 9

Answer:   C) 8



Explanation:
Summation of frequencies = 6+4+5+8+9+6+4 = 42
Median = mid value = average of 21st and 22nd value
Arranging data in increasing order we get

x     f

4     6

5     4

6     5

7     4

8     6

9     9

10    8

 
So mid value i.e 21st and 22nd value = 8
Subject: Average
Exam Prep: Bank Exams
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For the data given below. find the sum of mode. median and mean.6, 3, 8, 4, 3, 11, 7, 4, 5, 4.

A) 13.5 B) 13
C) 14 D) 14.5
 
Answer & Explanation Answer: C) 14

Explanation:
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Q:

The median of the numbers 14, 12, 12, 16, 13 and 18 is

A) 13 B) 14
C) 14.5 D) 13.5
 
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Q:

The mean height of 25 boys in a class is 150 cm, and the mean height of 35 girls in the same class is 145 cm. The combined mean height of 60 students in the class is ___ (app)

A) 146 B) 143
C) 147 D) 145
 
Answer & Explanation Answer: C) 147

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Q:

The average weight of two players P and Q of a football team is 38 kg. The average weight of P, Q and their coach T is 49 kg. What is the weight (in kg) of coach?

A) 71 B) 46
C) 76 D) 91
 
Answer & Explanation Answer: A) 71

Explanation:
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Q:

After replacing an old member by a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. The difference between the ages of the replaced and the new members?

A) 16 years B) 15 years
C) 14 years D) 13 years
 
Answer & Explanation Answer: B) 15 years

Explanation:

Let avg ages of 5 members at present is G

And age of new member is m and an older is n

Required = (5G + m - n)/5 = G - 3

m - n = 15 years

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Q:

A student's average marks in five subjects is 82. If the average marks of first two subject is 86.5 and the average marks of last two subjects is 84. Find the marks of third subject?

A) 69 B) 67
C) 71 D) 73
 
Answer & Explanation Answer: A) 69

Explanation:

The total marks of all 5 subjects = 82 x 5 = 410

Total marks of 1st two subjects = 86.5 x 2 = 173

Total marks of last two subjects = 84 x 2 = 168

Now, marks in 3rd subject = 410 - (173 + 168) = 410 - 341 = 69.

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Q:

Find the average of first 50 natural numbers?

A) 25 B) 25.5
C) 26 D) 26.5
 
Answer & Explanation Answer: B) 25.5

Explanation:

We Know that sum of the n natural numbers =n(n+1)2

  

Then sum of 50 natural numbers= 50(51)2= 1250

  

Average of the 50 natural numbers = 125050 = 25.5

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Q:

The average score of boys in an examination in a school is 81 and that of the girls is 83 and the average score of the school is 81.8. Then what will be ratio between the number of girls to the number of boys, in the examination?

A) 3:2 B) 2:3
C) 4:3 D) 3:4
 
Answer & Explanation Answer: B) 2:3

Explanation:

Let the number of boys = b

Let the number of girls = g

From the given data,

 

81b + 83g = 81.8(b + g)

81.8b - 81b = 83g - 81.8g

0.8b = 1.2g

b/g = 1.2/0.8 = 12/8 = 3/2

=> g : b = 2 : 3

 

Hence, ratio between the number of girls to the number of boys = 2 : 3.

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