Sawaal
59
Q:

The following question is based on the given data for an examination.

A. Candidates appeared                 10500

B. Passed in all the five subjects     5685

C. Passed in three subjects only     1498

D. Passed in two subjects only       1250

E. Passed in one subject only           835

F. Failed in English only                       78

G. Failed in Maths only                      275

H. Failed in Physics only                    149

I. Failed in Chemistry only                147

J. Failed in Biology only                     221

 

How many candidates passed in at least four subjects ?

A) 6555 B) 5685
C) 1705 D) 870

Answer:   A) 6555



Explanation:

Candidates passed in atleast four subjects

= (Candidates passed in 4 subjects) + (Candidates Passed in all 5 subjects)

= (Candidates failed in only 1 subject ) + ( Candidates passed in all subjects)

= (78 + 275 + 149 + 147 + 221) + 5685 = 870 + 5685 = 6555    

Subject: Arithmetical Reasoning
Related Questions
Q:

A, B, C, D and E play a game of cards. A says to B, "If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has." A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ? 

A) 28 B) 29
C) 31 D) 35
 
Answer & Explanation Answer: A) 28

Explanation:

Clearly, we have :

A = B - 3 ...(i)

D + 5 = E ...(ii)

A+C = 2E ...(iii)

B + D = A+C = 2E ...(iv)

A+B + C + D + E=150 ...(v)

From (iii), (iv) and (v), we get: 5E = 150 or E = 30.

Putting E = 30 in (ii), we get: D = 25.

Putting E = 30 and D = 25 in (iv), we get: B = 35.

Putting B = 35 in (i), we get: A = 32.

Putting A = 32 and E = 30 in (iii), we get: C = 28.

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63 13887
Q:

If you write down all the numbers from 1 to 100, then how many times do you write 3 ?

A) 11 B) 18
C) 20 D) 21
 
Answer & Explanation Answer: C) 20

Explanation:

Clearly, From 1 to 100, there are ten numbers with 3 as the unit's digit - 3, 13, 23, 33, 43, 53, 63, 73, 83, 93 and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.

 

So, required number = 10 + 10 = 20.

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741 61150
Q:

In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?

A) 20 B) 25
C) 30 D) Data inadequate
 
Answer & Explanation Answer: C) 30

Explanation:

Let the number of boys and girls participating in sports be 3x and 2x respectively.

 

Then, 3x = 15 or x = 5.

 

So, number of girls participating in sports = 2x = 10.

 

Number of students not participating in sports = 60 - (15 + 10) = 35.

 

Let number of boys not participating in sports be y.

 

Then, number of girls not participating in sports = (35 -y).

 

Therefore (35 - y) = y + 5 <=> 2y<=>  30<=> y = 15.

 

So, number of girls not participating in sports = (35 - 15) = 20.

 

Hence, total number of girls in the class = (10 + 20) = 30.

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134 26965
Q:

A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes ?

A) 32 rolls B) 54 rolls
C) 108 rolls D) 120 rolls
 
Answer & Explanation Answer: D) 120 rolls

Explanation:

Number of cuts made to cut a roll into 10 pieces = 9.

Therefore, Required number of rolls = (45 x 24)/9 = 120.

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446 44594
Q:

What is the product of all the numbers in the dial of a telephone ?

A) 1,58,480 B) 1,59,450
C) 1,59,480 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.

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109 18528
Q:

Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

A) Rs. 4, Rs. 23 B) Rs. 13, Rs. 17
C) Rs. 15, Rs. 14 D) Rs. 17, Rs. 13
 
Answer & Explanation Answer: B) Rs. 13, Rs. 17

Explanation:

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

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704 73794