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 Time and Distance Questions

Popular Latest Rated Important Formulae

FACTS  AND  FORMULAE  FOR  TIME  AND  DISTANCE

1.Speed = DistanceTime,  Time=DistanceSpeed, Distance= Speed×Time 

 

2. x km/hr = x×518 m/sec

 

3. x m/sec = x×185 km/hr

4. If the ratio of the speeds of A and B is a:b , then the ratio of the times taken by them to cover the same distance is or b : a

5. Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey is 2xyx+ykm/hr.

Q:

The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?

A) 83.5 km/hr B) 84.5 km/hr
C) 86.5 km/hr D) 87.5 km/hr
 
Answer & Explanation Answer: D) 87.5 km/hr

Explanation:

Let the speeds of two trains be 7X and 8X km/hr.

8x = 400/4

=> x= 12.5 km/hrX=4004=>X=12.5Km/hr

So speed of first train is 12.5*7 = 87.5 km/hr

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63 33530
Q:

A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge (in metres) is

A) 600 B) 750
C) 1000 D) 1250
 
Answer & Explanation Answer: D) 1250

Explanation:

speed    = (5x5/18)m/sec
             = 25/18 m/sec.


Distance covered in 15 minutes    = (25/18 x 15 x 60)m
                                                 = 1250 m.

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107 33527
Q:

The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached  to college  at the normal time. What is the changed (or increased) speed of Rajeev?

A) 28 km/h B) 30 km/h
C) 40 km/h D) 20 km/h
 
Answer & Explanation Answer: D) 20 km/h

Explanation:

Let the normal speed be x km/h, then 

80x-80(x+4)=1

⇒x2+4x-320=0

⇒x (x + 20) - 16 (x + 20) = 0

(x + 20 ) (x - 16) =0

 

x = 16 km/h

 Therefore (x + 4) = 20 km/h

 Therefore increased speed = 20 km/h

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55 31416
Q:

Akash leaves mumbai at 6 am and reaches Bangalore  at  10 am . Prakash leaves Bangalore at 8 am and reaches Mumbai at 11:30 am. At what time do they cross each other?

A) 10 am B) 8:32 am
C) 8:56 am D) 9:20 am
 
Answer & Explanation Answer: C) 8:56 am

Explanation:

Time taken by Akash = 4 h

Time taken by Prakash = 3.5 h

For your convenience take the product of times taken by both as a distance.

Then  the distance = 14km

Since, Akash covers half of the distance  in 2 hours(i.e at 8 am)

Now, the rest half (i.e 7 km) will be coverd by both prakash and akash

Time taken by them = 7/7.5 = 56 min

Thus , they will cross each other at  8 : 56am.

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71 29610
Q:

A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ?

A) 40 km B) 30 km
C) 20 km D) 10 km
 
Answer & Explanation Answer: C) 20 km

Explanation:

Average speed = 2aba+b, here a=25 b=4
= 2 x 25 x 4/(25+4) = 200/29 km/hr.

Distance covered in 5 hours 48 minutes
= Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms.

Distance of the post office from the village = (40/2) = 20 km.

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31 25357
Q:

If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of 60km. what is the usual speed of Deepesh?

A) 100 B) 120
C) 150 D) None of these
 
Answer & Explanation Answer: A) 100

Explanation:

Let the original speed  be x km/h, then

600x-600x+20=1 

 

⇒600x+20-xxx+20=1  

 

⇒x2+120x-12000=0

 

⇒x-120x-100=0

 

Therefore,  original speed = 100km/h

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32 23761
Q:

A man walks 6 km at a speed of 112kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man in kmph.

A) 4314

B) 4213

C) 2413

D) 3414

A) Option A B) Option B
C) Option C D) Option D
 
Answer & Explanation Answer: B) Option B

Explanation:

Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmph
time taken indivisually:
=> 6/1.5 = 4 m
=> 8/2 = 4 m
=> 40/8 = 5 m

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Average speed of man= total distance/ total time
=> 54/13 = 4213 kmph

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17 22582
Q:

A man takes 6 hours 15 minutes in walking a distance and riding back to the starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride both ways, is 

A) 4 hours B) 4 hours 30 minutes
C) 4 hours 45 minutes D) 5 hours
 
Answer & Explanation Answer: C) 4 hours 45 minutes

Explanation:

Time taken in walking both ways = 7 hours 45 minutes                     --------(i)

Time taken in walking one way and riding back= 6 hours 15 minutes-------(ii)

By equation (ii)*2 -(i), we have

Time taken to man ride both ways, = 12 hours 30 minutes - 7 hours 45 minutes

                                                        = 4 hours 45 minutes

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