Problems on Ages Questions

Q:

If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,

A) 30 B) 38
C) 40 D) 41
 
Answer & Explanation Answer: C) 40

Explanation:

Let daughter’s age = A and mother’s age = B
Given: 2A+B = 70 and A+2B = 95
Solving B, we will get B = 40.

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Q:

The average age of 80 boys in a class is 15. The average age of group of 15 boys in the class is 16 and the average of another 25 boys in the class is 14. What is the average age of the remaining boys in the class ?

A) 12.24 yrs B) 13.25 yrs
C) 16 yrs D) 15.25 yrs
 
Answer & Explanation Answer: D) 15.25 yrs

Explanation:

Total ages of 80 boys = 15 x 80 = 1200 yrs.
Total age of 16 boys = 15 x 16 = 240 yrs
Total age of 25 boys = 14 x 25 = 350 yrs.
Average age of remaining boys = 1200 - (240+350) / 80 - (25+15) = 610/41 = 15.25 yrs.

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11 13557
Q:

Proportion of Yuvaraj’s age to Ganguly’s age is 4:3. Yuvaraj willl be 26 years old after 6 years. What is the age of Ganguly now ?

A) 17 years B) 15 years
C) 19 years D) 12 years
 
Answer & Explanation Answer: B) 15 years

Explanation:

Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
A = 5
Current age of Ganguly = 3A
=> 3 x 5 = 15 years

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22 13519
Q:

Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ?

A) 17 years B) 13 years
C) 14 years D) 16 years
 
Answer & Explanation Answer: B) 13 years

Explanation:

Given R + S + M + D = 76

=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8

=> Let the ratio = x

=> M+7 = 5x

=> M = 5x-7

=> R = 7x-7

=> S = 6x-7

=> D = 8x-7

=> R + S + M + D = 76

=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76

=> 26x - 28 = 76

=> 26x = 104

=> x = 4

=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.

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23 13492
Q:

The age of a person is thrice the total ages of his 2 daughters. 0.5 decades hence, his age will be twice of the total ages of his daughters. Then what is the father’s current age? [0.5 Decades = 5 Years]

A) 35 years B) 40 years
C) 45 years D) 47 years
 
Answer & Explanation Answer: C) 45 years

Explanation:

Let, Total of current ages of the 2 daughters is A years.
Then, father’s current age = 3A years.
(3A + 5) = 2 (A +10)
3A + 5 = 2A + 20
A = 15
Therefore, father’s current age = 45 years.

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Q:

A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is

A) 20 B) 21
C) 22 D) 23
 
Answer & Explanation Answer: C) 22

Explanation:

Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22

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43 13370
Q:

0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]

A) 8:1 B) 10:2
C) 11:4 D) 13:4
 
Answer & Explanation Answer: D) 13:4

Explanation:

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9  => A = 3

 

Needed Ratio = (4A + 1) : (A + 1) = 13 : 4

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21 13161
Q:

A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

A) 45, 10 B) 10, 50
C) 9, 50 D) 50, 15
 
Answer & Explanation Answer: C) 9, 50

Explanation:

Let the age of A = A, B = B and C = C

From given

A = 3B

4 years ago,

C-4 = 2(A-4);

After 4 years

A + 4 = 31;

A = 27;
sub in above B, we get B = 9
C = 2(27 - 4) + 4 = 46 + 4 = 50

Hence B = 9yrs and C = 50yrs.

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