6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16 : 65. How much wine the cask hold originally?

A) 18 litres	B) 24 litres
C) 32 litres	D) 42 litres

Answer & Explanation Answer: B) 24 litres

Explanation:

Let the quantity of the wine in the cask originally be x litres

Then, quantity of wine left in cask after 4 operations = $[x {(1 - \frac{8}{x})}^{4}]$ litres

$∴ [\frac{x {(1 - \frac{8}{x})}^{4}}{x}] = \frac{16}{81}$

$\Rightarrow {[1 - \frac{8}{x}]}^{4} = {(\frac{2}{3})}^{4}$

$\Rightarrow x = 24$

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Filed Under: Alligation or Mixture

573 132728

Q:

A clock is set right at 8 a.m. The clock gains 10 minutes in 24 hours will be the true time when the clock indicates 1 p.m. on the following day?

A) 48 min. past 12.	B) 46 min. past 12.
C) 45 min. past 12.	D) 47 min. past 12.

Answer & Explanation Answer: A) 48 min. past 12.

Explanation:

Time from 8 a.m. on a day to 1 p.m. on the following day = 29 hours.

24 hours 10 min. of this clock = 24 hours of the correct clock.

$\frac{145}{6}$ hrs of this clock = 24 hours of the correct clock.

29 hours of this clock = $24 * \frac{6}{145} * 29$ hrs of the correct clock

= 28 hrs 48 min of the correct clock.

Therefore, the correct time is 28 hrs 48 min. after 8 a.m.

This is 48 min. past 12.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

707 132635

Q:

A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:

A) No profit, no loss	B) 5%
C) 8%	D) 10%

Answer & Explanation Answer: B) 5%

Explanation:

C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.

S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.

Gain =(80/1600*100) % = 5%

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Filed Under: Profit and Loss

1012 131565

Q:

A bag contains 6 white and 4 black balls .2 balls are drawn at random. Find the probability that they are of same colour.

A) 1/2	B) 7/15
C) 8/15	D) 1/9

Answer & Explanation Answer: B) 7/15

Explanation:

Let S be the sample space

Then n(S) = no of ways of drawing 2 balls out of (6+4) = $10 C_{2}$ 10 = $\frac{10 * 9}{2 * 1}$ =45

Let E = event of getting both balls of same colour

Then,n(E) = no of ways (2 balls out of six) or (2 balls out of 4)

= $6 C_{2} + 4 C_{2}$ = $\frac{6 * 5}{2 * 1} + \frac{4 * 3}{2 * 1}$ = 15+6 = 21

Therefore, P(E) = n(E)/n(S) = 21/45 = 7/15

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Filed Under: Probability

756 130071

Q:

Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:

A) 40	B) 80
C) 120	D) 200

Answer & Explanation Answer: A) 40

Explanation:

Let the numbers be 3x, 4x and 5x.

Then, their L.C.M. = 60x.

So, 60x = 2400 or x = 40.

The numbers are (3 x 40), (4 x 40) and (5 x 40).

Hence, required H.C.F. = 40.

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Filed Under: HCF and LCM

433 121741

Q:

Find the missing number?

15, 30, ? , 40, 8, 48

A) 21	B) 8
C) 19	D) 10

Answer & Explanation Answer: D) 10

Explanation:

Given nuber series is 15, 30, ? , 40, 8, 48

Here the number series follows a pattern that

15

15 x 2 = 30

30 $\div$ 3 = 10

10 x 4 = 40

40 $\div$ 5 = 8

8 x 6 = 48

Hence, the missing number in the series is 10.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

23 119778

Q:

For the circle shown below, find the length (in cm) of the largest cord of the circle.

A) 8	B) 12
C) 16	D) 18

Answer & Explanation Answer: C) 16

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

2 115150

Q:

The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?

A) 76	B) 79
C) 85	D) 87

Answer & Explanation Answer: A) 76

Explanation:

Average = total runs / no.of innings = 32

So, total = Average x no.of innings = 32 x 10 = 320.

Now increase in avg = 4runs. So, new avg = 32+4 = 36runs

Total runs = new avg x new no. of innings = 36 x 11 = 396

Runs made in the 11th inning = 396 - 320 = 76

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Filed Under: Average

423 114128

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