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 Problems on Ages Questions

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Q:

A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was :

A) 14 B) 19
C) 33 D) 38
 
Answer & Explanation Answer: A) 14

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19. 

 

Son's age 5 years back = (19 - 5) = 14 years

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Q:

In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

A) 19 B) 29
C) 39 D) 49
 
Answer & Explanation Answer: C) 39

Explanation:

Let B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)

 => x + 19 = 2x - 20

 => x =39.

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Q:

What is the age of Teja?

A: Four years ago, Raju was as old as Teja is at present.

B: Sita’s present age is two times of Raju’s present age.

C: The average age of Teja and Sita is 19 years.

A) Any two statements are sufficient to give answer B) Only C is sufficient
C) All of three statements are necessary to give answer D) Even using all the three statements answer cannot be found
 
Answer & Explanation Answer: C) All of three statements are necessary to give answer

Explanation:

From the given statements A, B & C

Let the present age of Teja = P

Raju present age = P + 4

Sita's present age = 2(P + 4)

Average of ages of Sita & Teja = 19

=> (2P + 8 + P)/2 = 19

= 3P + 8 = 38

=> P = 30/3 = 10

Hence, the present age of Teja = P = 10 yrs.

 

Therefore, by using all the three statements A, B & C we can find the age of Teja.

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Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

A) 12 B) 13
C) 14 D) 15
 
Answer & Explanation Answer: A) 12

Explanation:

(A+B) - (B+C) = 12

 

A - C = 12.

 

C is younger than A by 12 years.

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Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

Answer

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.


So, 5 years ago, as the ratio of their ages was 5 : 7, we can write  (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

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Subject: Problems on Ages

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Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Answer

Let the son's age be x years and the father's age be 4x years 



       5x = 40


        x = 8


\inline \therefore present age of the father = \inline 4x = \inline 4\times 8 = 32 years

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Subject: Problems on Ages

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Q:

The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:

A) 5 B) 10
C) 15 D) 20
 
Answer & Explanation Answer: C) 15

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75  => x = 15

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Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?

Answer

Total age of 10 students = 150 years


Total age of 15 students = 240 years


Total age of 5 new students = 240 - 150 = 90 years


\inline \therefore Average age of 5 new students =  = 18 years

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Subject: Problems on Ages

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